In order to make this comparison, two independent (separate) random samples need to be selected, one from each population. The null hypothesis H_{0} is that the two population proportions are the same; in other words, that their difference is equal to 0. The notation for the null hypothesis is H_{0}: p_{1} = p_{2}, where p_{1} is the proportion from the first population, and p_{2} is the proportion from the second population.
Stating in H_{0} that the two proportions are equal is the same as saying their difference is zero. If you start with the equation p_{1} = p_{2} and subtract p_{2} from each side, you get p_{1} – p_{2} = 0. So you can write the null hypothesis either way.
The formula for the test statistic comparing two proportions (under certain conditions) iswhere
is the proportion in the first sample with the characteristic of interest,
is the proportion in the second sample with the characteristic of interest,
is the proportion in the combined sample (all the individuals in the first and second samples together) with the characteristic of interest, and z is a value on the Zdistribution. To calculate the test statistic, do the following:

Calculate the sample proportions
for each sample. To do this let n_{1} and n_{2} represent the two sample sizes (they don’t need to be equal). For rho_1, divide the number of individuals in the first sample who have the characteristic of interest by n_{1}. For rho_2, divide the number of individuals in the second sample who have the characteristic of interest by n_{2}.

Find the difference between the two sample proportions,

Calculate the overall sample proportion
the total number of individuals from both samples who have the characteristic of interest (for example, the total number of smokers, male or female, combined from both samples), divided by the total number of individuals from both samples (n_{1} + n_{2}).

Calculate the standard error:

Divide your result from Step 2 by your result from Step 4.
This answer is your test statistic.
For example, the makers of Adderall, a drug for attention deficit hyperactivity disorder (ADHD), reported that 26 of the 374 subjects (7 percent) who took the drug experienced vomiting as a side effect, compared to 8 of the 210 subjects (4 percent) who were on a placebo (fake drug). Note that patients didn’t know which treatment they were given.
In the above study, a larger percentage of the people on the drug experienced vomiting, but is this percentage enough to say that the entire population on the drug would experience more vomiting? You can test it to see.
In this example, you have H_{0}: p_{1} – p_{2} = 0 versus H_{a}: p_{1} – p_{2} > 0, where p_{1} represents the proportion of all patients who would vomit when using Adderall, and p_{2} represents the proportion of all patients who would vomit when using the placebo.
Why does H_{a} contain a “>” sign and not a “<” sign? H_{a} represents the scenario in which those taking Adderall experience more vomiting than those on the placebo — that’s something the FDA (and any candidate for the drug) would want to know about.
But the order of the groups is important, too. You want to set it up so the Adderall group is first, so that when you take the Adderall proportion minus the placebo proportion, you get a positive number if H_{a} is true. If you switch the groups, the sign would have been negative.
Now calculate the test statistic:
First, determine that
Note the sample sizes are n_{1} = 374 and n_{2} = 210, respectively.

Take the difference between these sample proportions to get

Calculate the overall sample proportion to get

The standard error is

Finally, the test statistic is
Whew!
You might ask, “Hey, the difference in the sample proportions is 0.032 which shows that the drug induces more vomiting than the placebo. Why did the hypothesis test reject H_{0} since 0.032 is obviously greater than 0?” In this case, 0.032 is not significantly greater than 0. You also need to factor in variation using the standard error and the normal distribution to be able to say something about the entire population of patients.