## Practice Questions

- What is the value of 6
*x*– 3*y*^{2}when*x*= 12 and*y*= –5?**A.**–153**B.**297**C.**–3**D.**147*The next question is based on the following information.* - Which of the following expresses
in terms of

*p?***A.**0**B.**1**C.***p*^{–5}**D.***p*

## Answers and Explanations

- The correct answer is C.
Substitute the given values of

*x*and*y*into the expression:6

*x*– 3*y*^{2}= 6(12) – 3(–5)^{2}Then use the correct order of operations to simplify: Remember PEMDAS — (Parentheses, then Exponents, then Multiplication and Division, and then Addition and Subtraction). So first evaluate the exponent, then perform the multiplication, and finally perform the subtraction:

Hence, Choice (C) is correct.

- The correct answer is B.
Any expression to the power zero equals 1. Hence, the correct answer is Choice (B).