Imagine that the product of one reaction serves as the reactant for another reaction. Now imagine that the product of the second reaction serves as the reactant for a third reaction. What you have is a set of coupled reactions, connected in series like the cars of a train:
![]()
Therefore,
![]()
You can think of these three reactions adding up to one big reaction
![]()
What is the overall enthalpy change associated with this reaction
![]()
Here's the good news:
![]()
Enthalpy changes are additive. But the good news gets even better. Imagine that you're trying to figure out the total enthalpy change for the following multistep reaction:
![]()
Here's a wrinkle: For technical reasons, you can't measure this enthalpy change
![]()
directly but must calculate it from tabulated values for
![]()
and
![]()
No problem, right? You simply look up the tabulated values and add them. But here's another wrinkle: when you look up the tabulated values, you find the following:

Gasp! You need
![]()
but you're provided only
![]()
Relax. The enthalpy change for a reaction has the same magnitude and opposite sign as the reverse reaction. So if
![]()
then
![]()
It really is that simple:

Thanks be to Hess.
Try an example. Calculate the reaction enthalpy for the following reaction:
![]()
Use the following data:

Reaction enthalpies are given for two reactions. Your task is to manipulate and add Reactions 1 and 2 so the sum is equivalent to the target reaction. First, reverse Reactions 1 and 2 to obtain Reactions
![]()
and
![]()
and add the two reactions. Identical species that appear on opposite sides of the equations cancel out (as occurs with species P4 and Cl2):

Finally, divide the sum by 4 to yield the target reaction equation:
![]()
So, the reaction enthalpy for the reaction is 83.8 kJ.


