How to Juggle Dimensions and Replace Values in a Matrix in R
How to Get Lists with the lapply Function in R
How to Do Basic Arithmetic in R

How to Format and Perform Operations on Dates and Times in R

To format a date for pretty printing in R, you use format(), which takes a POSIXct or POSIXlt datetime as input, together with a formatting string.

Using the example where the object xct is the day and time of the Apollo landing, you can format this date and time in many different ways. For examples, to format it as DD/MM/YY, try:

> format(xct, "%d/%m/%y")
[1] "20/07/69"

In addition to the formatting codes, you can use any other character. If you want to format the xct datetime as a sentence, try the following:

> format(xct, "%S minutes past %I %p, on %d %B %Y")
[1] "39 minutes past 08 PM, on 20 July 1969"

Because R stores datetime objects as numbers, you can do various operations on dates.

Addition and subtraction in R

Because R stores objects of class POSIXct as the number of seconds since the epoch (usually the start of 1970), you can do addition and subtraction by adding or subtracting seconds. It’s more common to add or subtract days from dates, so it’s useful to know that each day has 86,400 seconds.

> 24*60*60
[1] 86400

So, to add seven days to the Apollo moon landing date, use addition, just remember to multiply the number of days by the number of seconds per day:

> xct + 7*86400
[1] "1969-07-27 20:17:39 UTC"

After you know that you can convert any duration to seconds, you can add or subtract any value to a datetime object. For example, add three hours to the time of the Apollo moon landing:

> xct + 3*60*60
[1] "1969-07-20 23:17:39 UTC"

Similarly, to get a date seven days earlier, use subtraction:

> xct - 7*86400
[1] "1969-07-13 20:17:39 UTC"

Comparison of dates in R

Similar to the way that you can add or subtract states you can also compare dates with the comparison operators, such as less than (<) or greater than (>).

Say you want to compare the current time with any fixed time. In R, you use the Sys.time() function to get the current system time:

> Sys.time()
[1] "2012-03-24 10:12:52 GMT"

Now you know the exact time when we wrote this sentence. Clearly when you try the same command you will get a different result!

Now you can compare your current system time with the time of the Apollo landing:

> Sys.time() < xct

If your system clock is accurate, then obviously you would expect the result to be false, because the moon landing happened more than 40 years ago.

The comparison operators are vectorized, so you can compare an entire vector of dates with the moon landing date. Try to use all your knowledge of dates, sequences of dates, and comparison operators to compare the start of several decades to the moon landing date.

Start by creating a POSIXct object containing the first day of 1950. Then use seq() to create a sequence with intervals of ten years:

> dec.start <- as.POSIXct("1950-01-01")
> dec <- seq(dec.start, by="10 years", length.out=4)
> dec
[1] "1950-01-01 GMT" "1960-01-01 GMT" "1970-01-01 GMT"
[4] "1980-01-01 GMT"

Finally, you can compare your new vector dec with the moon landing date:

> dec > xct

As you can see, the first two results (comparing to 1950 and 1960) are FALSE, and the last two values (comparing to 1970 and 1980) are TRUE.

  • Add a Comment
  • Print
  • Share
blog comments powered by Disqus
How to Store and Calculate Values in R
How to Cast Data to Wide Format in R
How to Plot Histograms with Your Data in R
How to Print and Save a Lattice Plot in R
How to Use the Clipboard to Copy and Paste Data in R