How to Find the Volume of a Solid between Two Surfaces of Revolution
If you want to find the volume of a solid that falls between two different surfaces of revolution, you can use the meatslicer method to do this. The meatslicer method works best with solids that have similar cross sections. Here’s the plan:

Find an expression that represents the area of a random cross section of the solid in terms of x.

Use this expression to build a definite integral (in terms of dx) that represents the volume of the solid.

Evaluate this integral.
The trick is to find a way to describe the donutshaped area of a cross section as the difference between two integrals: one integral that describes the whole shape minus another that describes the hole.
For example, suppose that you want to find the volume of the solid shown here.
This solid looks something like a bowl turned on its side. The outer edge is the solid of revolution around the xaxis for the function
The inner edge is the solid of revolution around the xaxis for the function
Here’s how to solve this problem:

Find an expression that represents the area of a random cross section of the solid.
That is, find the area of a circle with a radius of
and subtract the area of a circle with a radius of

Use this expression to build a definite integral that represents the volume of the solid.
The limits of integration are 0 and 4:

Solve the integral:
Now evaluate this expression:
Here’s another problem: Find the volume of the solid shown here.
This solid falls between the surface of revolution y = ln x and the surface of revolution
bounded below by y = 0 and above by y = 1.
The cross section of this solid is shown on the righthand side of the figure: a circle with a hole in the middle.
Notice, however, that this cross section is perpendicular to the yaxis. To use the meatslicer method, the cross section must be perpendicular to the xaxis. Modify the problem using inverses:
The resulting problem is shown in this figure.
Now you can use the meatslicer method to solve the problem:

Find an expression that represents the area of a random cross section of the solid.
That is, find the area of a circle with a radius of e^{x} and subtract the area of a circle with a radius of
This is just geometry. Remember that the area of a circle is πr^{2}:

Use this expression to build a definite integral that represents the volume of the solid.
The limits of integration are 0 and 1:

Evaluate the integral:
So the volume of this solid is approximately 9.179 cubic units.