Creating a Confidence Interval for the Difference of Two Means with Known Standard Deviations
If you know the standard deviations for two population samples, then you can find a confidence interval (CI) for the difference between their means, or averages. The goal of many statistical surveys and studies is to compare two populations, such as men versus women, low versus high income families, and Republicans versus Democrats. When the characteristic being compared is numerical (for example, height, weight, or income), the object of interest is the amount of difference in the means (averages) for the two populations.
For example, you may want to compare the difference in average age of Republicans versus Democrats, or the difference in average incomes of men versus women. You estimate the difference between two population means,
by taking a sample from each population (say, sample 1 and sample 2) and using the difference of the two sample means
plus or minus a margin of error. The result is a confidence interval for the difference of two population means,
If both of the population standard deviations are known, then the formula for a CI for the difference between two population means (averages) is
are the mean and size of the first sample, and the first population’s standard deviation,
is given (known);
and n_{2}_{ }are the mean and size of the second sample, and the second population’s standard deviation,
is given (known). Here z* is the appropriate value from the standard normal distribution for your desired confidence level. (Refer to the following table for values of z* for certain confidence levels.)
z*–values for Various Confidence Levels  
Confidence Level  z*value 

80%  1.28 
90%  1.645 (by convention) 
95%  1.96 
98%  2.33 
99%  2.58 
To calculate a CI for the difference between two population means with known standard deviations, do the following:

Determine the confidence level and find the appropriate z*value.
Refer to the above table.

Identify
Identify

Find the difference,
between the sample means.

Square
and divide it by n_{1}; square
and divide it by n_{2}.
Add the results together and take the square root.

Multiply your answer from Step 4 by z*.
This answer is the margin of error.

Take
plus or minus the margin of error to obtain the CI.
The lower end of the CI is
minus the margin of error, whereas the upper end of the CI is
plus the margin of error.
Suppose you want to estimate with 95% confidence the difference between the mean (average) length of the cobs of two varieties of sweet corn (allowing them to grow the same number of days under the same conditions). Call the two varieties Cornestats and Statsosweet. Assume by prior research that the population standard deviations for Cornestats and Statsosweet are 0.35 inches and 0.45 inches, respectively.

Because you want a 95% confidence interval, your z* is 1.96.

Suppose your random sample of 100 cobs of the Cornestats variety averages 8.5 inches, and your random sample of 110 cobs of Statsosweet averages 7.5 inches. So the information you have is:

The difference between the sample means,
from Step 2, is 8.5 – 7.5 = +1 inch. This means the average for Cornestats minus the average for Statsosweet is positive, making Cornestats the larger of the two varieties, in terms of this sample. Is that difference enough to generalize to the entire population, though? That’s what this confidence interval is going to help you decide.

Square
(0.35) to get 0.1225; divide by 100 to get 0.0012. Square
(0.45);divide by 110 to get 0.0018. The sum is 0.0012 + 0.0018 = 0.0030; the square root is 0.0554 inches (if no rounding is done).

Multiply 1.96 times 0.0554 to get 0.1085 inches, the margin of error.

Your 95% confidence interval for the difference between the average lengths for these two varieties of sweet corn is 1 inch, plus or minus 0.1085 inches. (The lower end of the interval is 1 – 0.1085 = 0.8915 inches; the upper end is 1 + 0.1085 = 1.1085 inches.) Notice all the values in this interval are positive. That means Cornestats is estimated to be longer than Statsosweet, based on your data.
To interpret these results in the context of the problem, you can say with 95% confidence that the Cornestats variety is longer, on average, than the Statsosweet variety, by somewhere between 0.8915 and 1.1085 inches, based on your sample.
The temptation is to say, “Well, I knew Cornestats corn was longer because its sample mean was 8.5 inches and Statosweet was only 7.5 inches on average. Why do I even need a confidence interval?” All those two numbers tell you is something about those 210 ears of corn sampled. You also need to factor in variation using the margin of error to be able to say something about the entire populations of corn.
Notice that you could get a negative value for
For example, if you had switched the two varieties of corn, you would have gotten –1 for this difference. You would say that Statsosweet averaged one inch shorter than Cornestats in the sample (the same conclusion stated differently).
If you want to avoid negative values for the difference in sample means, always make the group with the larger sample mean your first group — all your differences will be positive.
However, even if the group with the larger sample mean serves as the first group, sometimes you will still get negative values in the confidence interval. Suppose in the above example that the sample mean of Cornestats was 7.6 inches. Thus, the difference in sample means is 0.1, and the upper end of the confidence interval is 0.1 + 0.1085 = 0.2085 while the lower end is 0.1 – 0.1085 = –0.0085. This means that the true difference is reasonably anywhere from Cornestats being as much as 0.2085 inches longer to Statosweet being 0.0085 inches longer. It’s too close to tell for sure which variety is longer on average.